The thing I want

[learnedax]

A tetrahedron, each face marked with three symbols, one at each edge. The three edges adjacent to any face share a common symbol.

The four distinct symbols: I^{3 ⌈}Φ^{⌉ ⌈}e^{⌉ ⌈}π^⌉

Comments

[its-just-me.livejournal.com]

I'm offically confused

[herooftheage.livejournal.com]

So what is the problem? There's 12 edges, the symbols come in pairs, so two have to get repeated, but not matching other symbols on the face. Here's an easy solution: label the 4 vertices 1-4.

Triangle:

123 eøI
134 Ieπ
124 eIπ
234 øeI

giving 4 e, 4 I, 2 ø and 2π for this solution. The rest is just taking a 4 sided die and some contact paper. Pick whichever of the six combinations you like here.

Or did I just miss the joke?

You just might have

[learnedax.livejournal.com]

It's not a logistical challenge, although that is not in fact a valid layout. There are three of each, and labeling them by vertex instead of edge, although it works out to the same thing, is not the way I described it. (It's also harder to read because you have to squish the characters into a smaller space.)

The actual problem is in manufacturing, because I'd like it to be nicer looking, and not ridiculously expensive.

Re: You just might have

[herooftheage.livejournal.com]

Now I am confused, on two points.

1) I thought I was labeling edges. When I said 123 is eøI, I meant edge 12 is e, edge 23 is ø, and edge 31 is I.

2) How can you have 3 of each symbol? Anytime 1 triangle has a symbol on an edge, the corresponding other triangle will have the symbol too - that means each symbol must appear an even number of times, yes?

Yes, I missed that you wanted a cheap but nice version.

Re: You just might have

[learnedax.livejournal.com]

1) I'm sorry, I misread your labeling. That works just fine.

2) I can see where you would get that impression from what I wrote, but what I meant was that all three edges adjacent to a given face would have the same symbol, i.e. so that they unambiguously define a value for that face. This does correspond to a typical d4 layout.

3) It's not so much a joke as a thing that amused me.

Re: You just might have

[herooftheage.livejournal.com]

Ah,dawn breaks over Marblehead. You just want a 4 sided die with some different symbols on them - and yes, those symbols would be amusing on a die.

Re: You just might have

[its-just-me.livejournal.com]

I'm more confused than ever. This must be one of those things that requires an ejumacation or sumfin. I'll go back to flippin' burgers.

Re: You just might have

[laurion]

They're mathematical representations, particularly useful in advanced maths. You must be familiar with pi at least.

[londo.livejournal.com]

It's a shame it's not a d5 with e, pi, i, 1, 0. We could call it a dEuler.

[qedrakmar.livejournal.com]

http://www.koplowgames.com/ looks like a good start. They seem to do some custom dice. Might only cost you a few bucks. They also sell blank d4's which you could dremel out yourself. ;)